-4x^2+38x-48=0

Solution for -4x^2+38x-48=0 equation:

-4x^2+38x-48=0

a = -4; b = 38; c = -48;
Δ = b2-4ac
Δ = 382-4·(-4)·(-48)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-26}{2*-4}=\frac{-64}{-8}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+26}{2*-4}=\frac{-12}{-8}
=1+1/2
$